Linear Equations
One Variable | a๐ฅ + b = 0 | a โ 0 and a & b are real numbers |
Two Variable | a๐ฅ + b๐ฆ + c = 0 | a โ 0, b โ 0 and a, b & c are real numbers |
Three Variable | a๐ฅ + b๐ฆ + cz + d = 0 | a โ 0, b โ 0, c โ 0 and a, b, c & d are real numbers |
Pair of Linear Equations in two Variables
a1๐ฅ + b1๐ฆ + c1 = 0 a2๐ฅ + b2๐ฆ + c2 = 0 | Where a1, b1, c1, a2, b2 and c2 are all real numbers and a12 + b12 โ 0 & a22 + b22 โ 0 |
Important Points
1. A linear equation in two variable has infinite solutions. |
2. The graph of every linear equation in two variable is a straight line. |
3. ๐ฅ = 0 is the equation of the ๐ฆ-axis and ๐ฆ = 0 is the equation of the ๐ฅ-axis |
4. The graph ๐ฅ = a is a line parallel to ๐ฆ-axis |
5. The graph ๐ฆ = b is a line parallel to ๐ฅ-axis |
6. An equation of the type ๐ฆ = m๐ฅ represents a line passing through the origin. |
Linear equation in one Variable | Solution: One |
Linear equation in two Variable | Solution: Infinite solution possible |
Linear equation in three Variable | Solution: Infinite solution possible |
a1๐ฅ + b1๐ฆ + c1 = 0 a2๐ฅ + b2๐ฆ + c2 = 0 | a1/ a2 โ b1/ b2 | Intersecting lines | One unique solution only, consistent |
a1๐ฅ + b1๐ฆ + c1 = 0 a2๐ฅ + b2๐ฆ + c2 = 0 | a1/ a2 = b1/ b2 = c1/ c2 | Coincident lines | Infinite solutions, consistent |
a1๐ฅ + b1๐ฆ + c1 = 0 a2๐ฅ + b2๐ฆ + c2 = 0 | a1/ a2 = b1/ b2 โ c1/ c2 | Parallel lines | No solution, inconsistent |
1. Method of elimination by substitution | Steps: 1) Suppose the equation are a1๐ฅ + b1๐ฆ + c1 = 0 a2๐ฅ + b2๐ฆ + c2 = 0 2. Find the value of variable of either ๐ฅ or ๐ฆ in other variable term in first equation. 3. Substitute the value of that variable in second equation. 4. Now this is a linear equation in one variable. Find the value of the variable. 5. Substitute this value in first equation and get the second variable. |
2. Method of elimination by equating the coefficients | Steps: 1) Suppose the equation are a1๐ฅ + b1๐ฆ + c1 = 0 a2๐ฅ + b2๐ฆ + c2 = 0 2. Find the LCM of a1 and a2. Let it be k 3. Multiply the first equation by the value k/a1 4. Multiply the first equation by the value k/a2 5. Subtract the equation obtained. This way one variable will be eliminated and we can solve to get the value of variable in ๐ฆ. 6. Substitute this value in first equation and get the second variable. |
3. Cross Multiplication method | Steps: 1) Suppose the equation are a1๐ฅ + b1๐ฆ + c1 = 0 a2๐ฅ + b2๐ฆ + c2 = 0 2. This can be written as 3. 4. ๐ฅ => first and last expression ๐ฆ => second and last expression |