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Class IX – Science – Sample Paper – 2

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Class IX

Time Allowed: 3 hours                                                                                                                                                  Max Marks: 80

General Instructions:

  • The question paper comprises four sections A, B, C and D. there are 37 questions in the question paper. All questions are compulsory.
  • Section A question no 1 – 20 – all questions and parts thereof are of one mark each.
  • Section B question no 21 – 26 are short answer type questions carrying 2 marks each.
  • Section C question no 27 – 34 are short answer type questions, carrying 3 marks each.
  • Section D question no 35 – 37 are long answer type questions carrying 5 marks each
  • There is no overall choice. However, internal choices have been provided in some questions.
  • Wherever necessary, neat and properly labelled diagrams should be drawn.

Section – A

1. Name the type of epithelial tissue that lines blood vessels.

Ans. Squamous epithelium

OR

What are the cartilage cells called?

Ans. Chondrocytes

2. Name one cell organelle that is formed by Golgi apparatus.

Ans. Lysosomes.

3. Which of the following statements are true for pure substances?

(i) Pure substances contain only one kind of particles.

(ii) Pure substances may be compounds or mixtures.

(iii) Pure substances have the same composition throughout.

(iv) Pure substances can be exemplified by all elements other than nickel.

(A) (i) and (ii)

(B) (i) and (iii)

(C) (iii) and (iv)

(D) (ii) and (iii)

Ans. (B) (i) and (iii)

A pure substance is one which is made up of only one kind of atoms or molecules. They have the same composition throughout

4. At what speed a body of mass 1 kg will have a kinetic energy of 1 J?

Ans. As K.E. = 1/2 mv2

∴ 1 = 1/2 × 1 × v2

or v2 = 2

v = √2 = 1.4 m/s.

5. Which structures are present in the nuclear region of a living cell bear genes?

Ans. Chromosomes bear ‘genes’.

6. What are metalloids?

Ans. Metalloids: Elements having intermediate properties between those of metals and non- metals.

OR

What is meant by the term chemical formula?

Ans. Chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.

7. Give reason:

Horse continues to apply force in order to move a cart with constant speed.

Ans. The frictional force acts on cart wheel in opposite direction to motion of the cart.

8. Does the speedometer of a car measure its average speed?

Ans. No. It measures its instantaneous speed.

9. Why are skeletal muscles known as striated muscles?

Ans. Due to presence of alternate light and dark bands

10. Which organelle synthesizes lipid molecules inside the cell?

Ans. Lipid molecules in the cell are synthesised by the smooth endoplasmic reticulum present in the cell.

11. Find the acceleration produced by a force of 12 N exerted on an object of mass 3 kg.

Ans. F = ma => 12 = 3 × a, a = 12/3 = 4 m/s2

OR

State whether the force is balanced or unbalanced in the following situation:

A bicycle is moving in a straight line with constant velocity.

Ans. Force is balanced.

12. State how is gravitational force between two bodies related to their masses.

Ans. F ∝ m1 × m2

OR

Give reason: A sheet of paper falls slower than when it is crumpled into a ball.

Ans. It is due to resistance offered by air on paper sheet.

13. A car and a truck are moving with the same velocity of 60 km/hr. Which one has more kinetic energy? (Mass of truck > Mass of car)

Ans. Truck has more kinetic energy since kinetic energy is directly proportional to mass and mass of truck is greater than mass of car.

14. List the various factors which are responsible for loss of stored food grains.

Ans. Biotic—insects, rodents, fungi, mites, bacteria.

Abiotic—inappropriate moisture + temperature.

15. Assertion: Sound waves can propagate in space.

Reason: Sound waves need medium for propagation.

(A) Both A and R are true, and R is correct explanation of the assertion.

(B) Both A and R are true, but R is not the correct explanation of the assertion.

(C) A is true, but R is false.

(D) A is false, but R is true.

Ans. (D) A is false, but R is true.

Sound waves need medium for propagation. In space, there is no air; therefore, sound waves cannot propagate into space.

16. Assertion: Human RBCs burst in hypotonic solution.

Reason: Cells burst due to endosmosis.

(A) Both A and R are true, and R is correct explanation of the assertion.

(B) Both A and R are true, but R is not the correct explanation of the assertion.

(C) A is true, but R is false.

(D) A is false, but R is true.

Ans. (A) Both A and R are true, and R is correct explanation of the assertion.

Human red blood cells when they are placed in hypotonic solution, they burst due to endosmosis.

OR

Assertion: Multicellular organism have higher survival rate than unicellular organisms.

Reason: In Multicellular organism, dead cells are replaced by new cells.

(A) Both A and R are true, and R is correct explanation of the assertion.

(B) Both A and R are true, but R is not the correct explanation of the assertion.

(C) A is true, but R is false.

(D) A is false, but R is true.

Ans. (A) Both A and R are true, and R is correct explanation of the assertion.

Multicellular organisms are made of many cells. Death or injury of any cells can be replaced by new cells. Thus, because of increased efficiency, organization and division of labour, multicellular organisms have higher survival rate.

17. Assertion (A): Burning a match stick is a chemical change.

Reason (R): Chemical changes are irreversible changes whereby the chemical composition also changes and a new substance is formed.

(A) Both A and R are true, and R is correct explanation of the assertion.

(B) Both A and R are true, but R is not the correct explanation of the assertion.

(C) A is true, but R is false.

(D) A is false, but R is true.

Ans. (A) Both A and R are true, and R is correct explanation of the assertion.

Burning a match stick is an irreversible (chemical) change because when we burn it, it produces smoke and turns into ash.

Q. No 18 – 20 contain five sub-parts each. You are expected to answer any four sub parts in these questions. 18. Read the following and answer any four questions from 18 (i) to 18 (v)

The mass of an object is defined as the amount of matter present in it, and is denoted by M. Mass is a physical quantity, which is independent of other physical quantities. Thus, mass is a fundamental physical quantity. Very often, the term weight is used instead of mass. But, weight and mass are different. The weight of an object is defined as the force with which the object is attracted by the earth. The weight of an object varies from place to place, whereas its mass is always constant. It does not change with position or place. The mass of an object is measured by a common balance by comparing it with a known standard mass.

(i) Define mass.

Ans. Mass is the quantity of matter contained in an object.

(ii) What is weight?

Ans. Weight is the force with which an object is attracted towards the centre of earth.

(iii) What is the SI unit of weight?

(A) kg

(B) Newton

(C) kg-Newton

(D) Pascal

Ans. (B) Newton

Ans. Weight is a force and so is measured in newton (N).

(iv) State the formula to find weight of a body.

Ans. W = mg

(v) An object has mass of 20 kg on earth. What will be its mass and weight on the surface of the moon? (gon moon = 1.6 m/s2)

Ans. The mass of an object on the moon will be 20 kg and the weight of the object on the moon will be (20)(1.6) = 32N.

19. Read the following and answer any four questions from 19 (i) to 19 (v)

Bone is a solid, hard porous tissue. It forms the natural skeleton and gives the body its basic structure and also supports the body. Its matrix is impregnated with phosphates and carbonates of calcium and magnesium which provides hardness to it. The matrix also contains ossein protein. The matrix is arranged in concentric rings which are called lamellae.

Bone cells lie between the lamellae in fluid-fluid spaces called lacunae. Bone cells are also called osteocytes

i) What are bone cells also called?

A) Lacunae

B) Osteocytes

C) Neutrophils

D) Erythrocytes

Ans. B) Osteocytes

Osteoblasts are bone-forming cell, osteoclasts resorb or break down bone, and osteocytes are mature bone cells.

(ii) The matrix inside the bone is arranged in concentric rings called

(A) Cytoplasm

(B) Osteocyte

(C) Lacunae

(D) Lamellae

Ans. (D) Lamellae

The concentric rings of cells that compact bone forms surrounding central canals are called lamellae.

(iii) Write the function of ligaments and tendon.

Ans. Ligament connects two bones while tendon connects a muscle to a bone.

(iv) The matrix of bone is impregnated with………….

Ans. The matrix of bone is impregnated with phosphates and carbonates of calcium and magnesium

(v) Bone cells lie between the lamellae in fluid-filled spaces called

(A) lamina

(B) osteocytes

(C) lacunae

(D) ossein

Ans. (D) ossein

The osteon consists of a central canal called the osteonic (haversian) canal, which is surrounded by concentric rings (lamellae) of matrix. Between the rings of matrix, the bone cells (osteocytes) are located in spaces called lacunae.

20. Read the following passage and answer any 4 questions from 20 (i) to 20 (v).

Rahul added a crystal of CuSO4 in a glass of water and allowed it to settle at the bottom. After sometime he observed that the blue colour appears just above the solid crystal and with the passage of time whole water in glass turns blue.

(i) Name the phenomenon due to which this happens.

Ans. When a crystal of copper sulphate is placed at the bottom of a beaker containing water, the water slowly turns blue because of the diffusion of copper sulphate particles into water

(ii) Identify the characteristic of particles of matter associated with this observation.

Ans. Particles of matter are continuously moving

(iii) The state of matter in which particles just move around randomly because of very weak force of attraction is liquid. (True or False)

Ans. False.

The state of matter in which particles just move around randomly because of very weak force of attraction is gas.

(iv) The arrangement of particles is less ordered in the _______________state. However, there is no order in the __________state.

Ans. Liquid, gaseous.

(v) Arrange the following substances in the increasing order of force of attraction between their particles: Oxygen, sugar, water.

Ans. Oxygen < water < sugar.

Section – B

21. Why are epidermal and cork cells called protective tissues?

Ans. They are called protective tissues because:

(i) They protect from mechanical injury and infection.

(ii) They prevent loss of water.

22. A cheetah can accelerate from rest at the rate of 4 m/s2. What will be the velocity attained by it in 10 s ?

Ans. Initial velocity (u) = 0, acceleration (a) = 4m/s2

v = u + at = 0 + 4 × 10

v = 40 m/s.

23. Differentiate between rough and smooth endoplasmic reticulum.

Ans. Rough endoplasmic reticulum looks rough under a microscope because it has particles called ribosomes attached to its surface and smooth endoplasmic reticulum does not have ribosomes attached to it. It helps in the manufacture of fat molecules or lipids important for cell function.

OR

What happens when:

(i) Methylene blue stain is added to human cheek cell.

Ans. Because of its affinity for DNA and RNA, methylene blue will produce a darker stain leading the DNA in the nucleus to stand out so that nucleus can be clearly seen.

(ii) Rheo leaves are boiled in water and a drop of sugar is added to it.

Ans. On boiling, all the cells of Rheo leaves become dead. On adding sugar syrup nothing will happen as liquid cannot pass through dead cell membrane.

24. Give reasons:

(i) Survival of fish and other aquatic animals become difficult during summers.

Ans. Because at high temperature, solubility of a gas in a liquid decreases. Thus, less amount of dissolved oxygen is available.

(ii) When a beam of light is thrown on a clear solution of copper sulphate kept in a dark room, it does not glow.

Ans. Because it doesn’t show Tyndall effect.

25. From the symbol 16S32 state:

(i) Atomic number of sulphur

Ans. Atomic number of sulphur is 16

(ii) Mass number of sulphur

Ans. The mass number of sulphur is 32

OR

Which of the following are isotopes and which are isobars?

Argon, Protium, Calcium, Deuterium.

Ans. Isotopes: Protium and deuterium.

Isobars: Argon and calcium.

26. (i) What is meant by composite fish culture?

Ans. Composite fish culture is the poly culture system in which combination of 5 or 6 fish species are selected and grown in a single fish bond.

(ii) What is the basis of selecting the different species of fish?

Ans. The selection of different species of fish is done so that they do not compete for food and the food available in all the parts of the pond is utilised. This increases the fish yield.

Section – C

27. (i) If an atom contains one electron and one proton, will it carry any charge or not?

Ans. Number of protons = Number of electrons

Hence, there will be no charge i.e., atom is neutral.

(ii) On the basis of Thomson’s model of an atom explain how the atom is electrically neutral.

Ans. The positive charge due to protons and negative charge due to electrons balance each other.

Hence, atom becomes electrically neutral

OR

If an element ‘X’ is available in the form of say, two isotopes such as 35Br79 (49.7%) and 35Br81 (50.3%). Calculate the average atomic mass of the atom of X.

Ans. Average mass = % fraction × Atomic weight1 + % fraction × Atomic weight2

Average mass = 49.7/100 x 79 + 50.3/100 x 81

= (39.263 + 40.743)

= 80.006 u

28. The percentage of three elements-calcium, carbon and oxygen in a sample of calcium carbonate is given as : Calcium = 40%; Carbon =12.0%; Oxygen = 48%. If the law of constant proportion is true, what weight of these elements will be present in 1.5 gm of another sample of calcium carbonate? (Atomic mass of Ca = 40 u, C = 12 u, O = 16 u)

Ans. Mass of calcium in 1.5 gm of sample

= 40/100 × 1.5 = 0.6 gm

Mass of carbon in 1.5 gm of sample = 12/100 × 1.5 = 0.18 gm

Mass of oxygen in 1.5 gm of sample = 48/100 × 1.5 = 0.72 gm

29. (i) Classify the following as homogeneous or heterogeneous mixture: Air, Soil, Filtered tea, Wood.

Ans. Air, Filtered tea: Homogeneous.

Soil, Wood: Heterogeneous.

(ii) Which of the following materials are categorized as pure substance?

(A) Mercury

(B) Milk

(C) Calcium oxide

(D) Ink

Ans. Mercury and Calcium oxide: Pure substances

30. Label the following and give one function of each part labelled (i), (ii) and (iii).

Ans. (i) (a) & (c) Lateral meristem: Helps in growth and development of plant’s shoot and root girth.

(ii) Intercalary meristem: Helps in increasing internodes of plants like sugarcane.

(iii) Apical meristem: Helps in growth of the stem and the root.

31. A motor car of mass 1200 kg is moving along a straight line with uniform velocity of 90 km/h. Its velocity is slowed down to 18 km/h in 4 s by an unbalanced external force. Calculate the acceleration and change in momentum. Also calculate the magnitude of external force acting on it.

Ans. u = 90 km/hr = 25 m/sec.

v = 18 km/hr = 5 m/sec.

a = (v – u)/ t = (5 – 25)/4 = -20/4

= –5 m/s2

Change in momentum = mv – mu

= 1200 (v – u)

= 1200 (5 – 25)

= 1200 × –20

= –24000 kg m/sec 

F = ma

= 1200 × –5

= – 6000 kg m/s2

= 6000 N

32. Study the speed time graph of a car alongside and answer the following questions:

(i) What type of motion is represented by OA?

Ans. Uniform acceleration

(ii) Find acceleration from B to C.

Ans. a = (v – u)/t

= (0 – 3)/20 = 3/20 m/s2

(iii) Calculate the distance covered by the body from A to B. Give reasons for your answer.

Ans. D = v × t = 3 × (60 – 20) = 120 m

(It is the motion with constant speed)

33. In which direction do the following forces act when an object is in motion:

(i) Frictional force

Ans. Opposite to the direction of motion.

(ii) Gravitational force

Ans. Downwards

(iii) Centripetal force (R)

Ans. Towards the centre

34. Unpredictable monsoon/droughts/low rainfall is adversely affecting the Indian agriculture.

(a) Mention any two initiatives that have been adopted to increase the availability of water for agricultural purposes.

Ans. Rain water harvesting and water shed management.

(b) State two advantages of making check dams.

Ans. Two advantages of check dams:

(i) Increase the ground water level

(ii) Reduce soil erosion

(iii) Prevent rain water from flowing away

(c) Briefly describe canal and river lift system

Section – D

35. (a) List any three characteristics of colloid.

Ans. (i) It is heterogeneous mixture.

(ii) Particles of colloids scatter a beam of light. (Tyndall effect)

(iii) It is stable.

(b) Name the two components of a colloid.

Ans. Dispersing medium and dispersed phase

(c) Identify colloid from the following mixtures: Muddy water, Sugar in water, Ink, Blood, Soda water, Foam.

Ans. Ink, blood, foam

36. (a) Write the formula to find the magnitude of gravitational force between the earth and an object on the earths’

surface.

Ans. F = GMm/R2

(b) Derive how does the value of gravitational force ‘F’ change between two objects when the:

(i) distance between them is reduced to half, and

Ans. According to the law of gravitation, the force of attraction acting between two bodies is given by,

F´= GM1m2/R2 = G M1m2/(R/2)2

= 4G M1m2/R2 = 4F

Thus, when the distance between the objects is reduced to half, the gravitational force increases by four times the original force.

(ii) mass of one object is increased four time.

Ans. F’ = G M × 4 m/R2 = 4F So, as the mass of any one of the object is increased four times, the force is also increased four times.

OR

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line.

(i) What is the total work done against the force of gravity and by the force of gravity on the object? Explain with proper mathematical expressions.

Ans. Work done = mgh

Difference in height of initial and final position is zero.

Therefore, Work done = mg (h2 – h1) = mg(0) = 0

(ii) Certain force acting on a 20 kg mass changes its velocity from 5 ms-1 to 2 ms-1. Calculate the work done by the force.

Ans. Work done = Change in K.E

Work done = v2 final – v1 initial

= 1/2 × 20 × 4 – 1/2 × 20 × 25 = 40 – 250 = – 210 J

37. Given below is an animal cell as observed under an electron microscope.

(i) Name the parts labelled as 1 to 10

Ans. 1. Mitochondria 2. Cytoplasm 3. Ribosome 4. Smooth Endoplasmic reticulum 5. Rough Endoplasmic reticulum 6. Nucleolus 7. Nucleoplasm 8. Nuclear membrane 9. Centrosome 10. Golgi apparatus.

(ii) Which parts are concerned with the following functions:

(a) Release of energy

Ans. Mitochondria

(b) Protein synthesis

Ans. Ribosome

(c) Transmission of hereditary characters from parents to their offspring’s

Ans. Nucleus

(iii) Mention any two structures, found only in plant cell not in animal cell

Ans. (a) Cell wall and (b) Plastids