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Light: Reflection and Refraction

Important Questions/PYQs

One Mark Questions

1. Write down four important characteristics of image formed by a plane mirror.

View Answer

Ans. Image is virtual, erect, laterally inverted and of same size as object.


2. Describe a spherical mirror.

View Answer

Ans. Spherical mirror is a part of a sphere. If reflection takes place from inside, it is said to be concave mirror, and if the reflection takes place from outside surface it is a convex mirror.


3. Define the following terms in relation to concave spherical mirror.

a) Pole

b) Centre of curvature

c) Radius of curvature

d) Principal axis

e) Principal focus

f) Aperture

g) Focal length

View Answer

Ans. a) The midpoint of mirror is known as pole.

b) The centre of curvature of a spherical mirror is the centre of that sphere of which mirror is a part.

c) The distance between pole and centre of curvature is called radius of curvature of the mirror.

d) The straight line joining the pole and centre of curvature is called principal axis.

e) The point on the principal axis through which parallel rays to the principal axis passes or appear to pass after reflection.

f) The diameter of the mirror or size of the mirror is called aperture.

g) The distance between focus and pole of a mirror is the focal length of the mirror.


4. What are the advantages and disadvantages of using a convex mirror for seeing traffic at the rear?

View Answer

Ans.

Advantage of Convex Mirror: It provide wider view of the rear traffic.

Disadvantage: It does not give the correct distance of the vehicle at the rear


5. What are the units of power of a lens?

View Answer

Ans. If the focal length is measured in meter then the unit of power of a lens is diopter.


6. Give two uses of a convex lens.

View Answer

Ans. Convex lens are used in (i) spectacles, (ii) telescopes, (iii) microscopes, (iv) camera


7. Give one use of a concave lens

View Answer

Ans. Concave lenses are used in (i) shaving mirror, (ii) flash lights


8. What is a prism?

View Answer

Ans. A prism is an optical device with two triangular bases along with three rectangular lateral surfaces commonly inclined at an angle of 60 degrees.


9. Define the term reflection.

View Answer

Ans. The bouncing back of a ray of light in the same medium after striking on a surface of an object.


10. Define the terms:

a) Angle of incidence

b) Angle of reflection

c) Plane of incidence

View Answer

Ans. a) The angle between incident ray and normal at the point of incidence is called angle of incidence ∠i.

b) the angle between the reflected ray and normal at the point of incidence is called angle of reflection ∠r.

c) A plane containing, incident ray, normal, and reflected ray is known as plane of incidence.


11. State the laws of reflection.

View Answer

Ans. Laws or reflection

a) The incident ray, the reflected ray and the normal at the point of incidence are always in the same plane.

b) Angle of incidence is equal to the angle of reflection.


12. Explain why we see the sign of AMBULANCE as laterally inverted in front of these vehicles.

View Answer

Ans. The image of the laterally inverted word will be produced as an erect image and the person seeing it in rear view mirror as AMBULANCE.


13. What is the radius of curvature of a plane mirror?

View Answer

Ans. The radius of curvature of a plane mirror is infinite.


14. How many images are formed by two parallel mirrors?

View Answer

Ans. The images formed by two parallel plane mirrors will be infinite.


15. Name a mirror that can give an erect and enlarged image of an object.

View Answer

Ans. Concave mirror.


16. The radius of curvature of a spherical mirror is 20 cm. What is its focal length?

View Answer

Ans. Focal length f = R/2 = 20/2 = 10 cm


17. Light enters from air to glass having refractive index 1.50. What is the speed of light in glass? Speed of light in air 3 x 108 m/s

View Answer

Ans. Speed of light in glass

V = c/n = (3 x 108)/1.5 m/s = 2 x 108 m/s


18. The refractive index of diamond is 2.42. What is the meaning of this statement?

View Answer

Ans. The meaning of refractive index of diamond is 2.42 is that speed of light in diamond is ½.42 times the speed of light in air/vacuum D,

i.e., speed of light in diamond

v = c/n = (3 x 108)/2.42 = 1.24 x 108 m/s


Two Marks Questions

19. If the image formed by a convex lens is of the same size as that of the object. What is the position and nature of the image with respect to the lens?

View Answer

Ans. The image will be real, inverted and will be formed at centre of curvature of the lens.


20. How can you identify the three types of mirrors without touching them?

View Answer

Ans. a) If the image formed is erect, of same size and at equal distance behind the mirror as object and is in front of the mirror, then mirror is plane.

b) If the image is of larger size and erect and changes to inverted and smaller size by changing the position of mirror from the object it is concave mirror.

c) If the image is smaller and erect for all positions of mirror from the object, it is a convex mirror.


21. a) What happens to a ray of light when it travels from one medium to another having equal refractive indices?

b) State the cause of refraction of light.

View Answer

Ans. a) If a ray travels from one medium to another medium of same refractive indices then it will not bend and travels in a straight line.

b) Change in speed of light is the cause of refraction.


22. a) What should be the position of the object, when a concave mirror is to be used

(i) as a shaving mirror, and

ii) in torches producing parallel beam of light?

b) A man standing in front of a mirror finds his image having a very small head and legs of normal size. What type of mirror are used in designing such a mirror?

View Answer

Ans. i) Face must be placed in between the pole and focus of the mirror so that enlarged, erect image of face can be formed.

ii) At focus, because rays coming from the focus after reflection will become parallel.

b) It is a combination of convex mirror (small head) and plane mirror (legs of normal size).


23. Name the type of lens that can be used as magnifying glass. Give reason(s) and draw a ray diagram to support your answer.

View Answer

Ans. A convex lens of small focal length can be used as magnifying glass. When an object is placed in between pole and focus of the convex lens then enlarged, erected and same side of object image is formed.


24. An object is placed at the following distances from a concave mirror of focal length 15 cm.

(a) 10 cm

(b) 20 cm

(c) 30 cm

(d) 40 cm

Which position of the object will produce:

(i) Virtual image

(ii) A diminished real image

(iii) An enlarged real image

(iv) An image of same size.

View Answer

Ans. Given, concave mirror of f = 15 cm

a) When object is placed at a distance of 10 cm from mirror (between P and f) image is virtual, enlarged and erected.

b) For object in between 2F and ∞ i.e., 40 cm image is inverted, diminished and real.

c) For object in between F and C (20 cm), image is inverted, enlarged and real beyond 2F (C).

d) For object at 2F (30 cm), the image is of same size.


25. (a) What is meant by refraction of light?

(b) If on applying Cartesian sign convention for spherical lenses, the image distance obtained is negative, state the significance of the negative sign.

View Answer

Ans. (a) When a ray of light passes from one medium to another it bends from its path. The phenomenon of bending a ray of light when it passes from one medium to another is called refraction of light.

(b) In a lens if the image distance is negative then its meaning is that image formed is at the same side of object, virtual and erect. The is concave lens.


26. What is minimum number of rays required for locating the image formed by a concave mirror for an object? Draw a ray diagram to show the formation of a virtual image by a concave mirror.

View Answer

Ans. We require minimum two rays for locating the image formed by a concave mirror.


27. (a) Name the spherical mirror used as:

1. Shaving mirror

2. Rear view mirror in vehicles

3. Reflector in search lights

(b) Write any three differences between a real and virtual image.

View Answer

Ans. (a) 1. Concave mirror

2. Convex mirror

3 Concave parabolic


(b) Differences between a real and virtual image:

View Answer
Real ImageVirtual Image
1. It can be taken on screen1. It cannot be taken on a screen
2. It is always inverted2. It is always erected
3. When reflected or refracted rays actually meet at a point, then real image is formed.3. When reflected or refracted rays appear to meet at a point then virtual image is formed.

28. What is meant by power of a lens? Give its SI unit. When two or more lenses are placed in contact, what will their combined power?

View Answer

Ans. Power of a lens is the ability of the lens to converge or diverge a ray of light incident on it. It is the reciprocal of the focal length of the lens, ie., P = 1/f. The SI unit of power is D (dioptre) if f is measured in metre.


29. For the same angle of incidence in media P, Q and R, the angles of refraction are 45°, 35° and 15° respectively. In which medium will the velocity of light be minimum. Give reason.

View Answer

Ans. As n = c/v = sin i/sin r => v = c sin r/sin i

For same incident angle, v will be minimum for minimum value of angle r i.e., medium R.


30. Define absolute refractive index. Absolute refractive indices of medium A and medium B are na and nb respectively, what is the refractive index of medium B with respect to medium A? How does the velocity of light vary with change in the optical density of the media?

View Answer

Ans. Absolute refractive index of a given medium, w.r.t air/vacuum is known as absolute refractive index of the medium.

n = Speed of light in vacuum or air/Speed of light in medium

n = c/v as c > v

n > 1

= Velocity of light in B/Velocity of light in A = vb/va = na/nb

Higher the optical density, lesser is the velocity of light in the medium.


31. As the velocity of light increases, the refractive index of the medium decreases. Light enters from air to water having refractive index 4/3. Find the speed of light in water. The speed of light in vacuum is 3 x 108 m/s

View Answer

Ans. Given n = 4/3, c = 3 x 108 m/s

v = ?

n = c/v => v = c/n

v = (3 x 108 x 3)/4

= 2.25 x 108 m/s


32. What is meant by radius of curvature of a spherical mirror? How is it related to the focal length of the mirror?

View Answer

Ans. Radius of curvature of a spherical mirror is the radius of the sphere of which mirror is a part. It is the distance between pole and centre of curvature of a mirror. The radius of curvature is equal to the twice the focal length

R = 2f


33. With the help of ray diagram show that angle of incidence is equal to the angle of reflection when a ray is incident on the concave/convex mirror.

View Answer

Ans.


34. A doctor has prescribed a corrective lens of power + 1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?

View Answer

Ans. f = 1/P m

= 1/+1.5 m

= + 10/15 m

=+ 2/3 m

f = +66.7 cm

+f means the lens is convex (converging) lens.


35. With the help of a ray diagram, show that the formation of the image of an object by a concave mirror when it is placed at the centre of curvature.

View Answer

Ans.


36. Draw a ray diagram for the image formed by a concave mirror when the object is placed beyond its centre of curvature.

View Answer

Ans.


37. Differentiate between reflection and refraction of light.

View Answer

Ans.

ReflectionRefraction
1. It is the phenomenon of bouncing back of ray of light in the same medium after striking with a surface.1. It is the phenomenon of bending a ray of light when it travels from one medium to another medium.
2. ∠i (angle of incidence) = ∠r (angle of reflection)2. ∠i (angle of incidence )≠ ∠r (angle of refraction)
3. Reflection can take place from any surface.3. Refraction can take place from a transparent interface.

38. Define optical centre and principal axis of a lens. Show the path of the refracted ray when a ray of light is incident towards the optical centre of concave lens.

View Answer

Ans. Midpoint of a lens through which a ray of light passes undeviated is known as optical centre.

A straight line joining two centre of curvatures of the lens is called principal axis of lens.


39. An object is placed at the focus of a convex lens. Draw a ray diagram to locate the position of the image formed, if any. State its position and nature.

View Answer

Ans. Image is formed at infinity, image will be real, inverted and enlarged.


40. Define the term magnification. Write its formula also.

View Answer

Ans. Magnification m of a mirror gives the relative extent to which the size of image of an object is magnified w.r.t size of object. It is the ration of size of image (h2) to size of an object (h1)

m = Size of image /Size of object = h2/h1 = -v/u


41. Write the relation between object distance and image distance from a lens and focal length of a lens.

View Answer

Ans.

1/f = 1/v – 1/u


42. With the help of ray diagrams differentiate between a converging lens and a diverging lens.

View Answer

Ans.


43. If the image formed by a spherical mirror for all positions of the object placed in front of it, is always erected and diminished, what type of mirror is it? Draw a labelled ray diagram to support your answer.

View Answer

Ans. It is a convex mirror. Ray diagram for any position of object.


44. State the laws of refraction of light. Explain the term ‘absolute refractive index of a medium’ and write an expression to relate it with the speed of light in vacuum.

View Answer

Ans. Laws of refraction:

a) The incident ray, refracted ray and normal to the point of incidence all lie in the same plane.

b) The ratio of sin of incident angle to sin of angle of refraction for a given pair of medium is constant.

Sin i/Sin r = constant

Absolute refractive index of a medium is the ratio of speed of light in air or vacuum to speed of light in the medium.

Absolute refractive index = Speed of light in air/vacuum/Speed of light in medium


Three Marks Question

45. A ray of light is incident obliquely on a glass slab. Draw a ray diagram showing the path of the light ray. Clearly, mark angle of incidence, angle of refraction, angle of emergence and lateral displacement of the ray. Give a formula to find refractive index of glass slab in terms of angle of incidence and angle of refraction.

View Answer

Ans. When a ray passes from optical rarer to denser medium, it bends towards the normal and vice versa.

∠i = angle of incidence

∠r = angle of refraction

∠e = angle of emergence

d = lateral displacement


46. (a) For the same angle of incidence 45°, the angle of refraction in two transparent media; I and II is 20° and 30° respectively. Out of I and II, which medium is optically denser and why?

(b) Light enters from air to diamond which has refractive index of 2.42. Calculate the speed of light in diamond, if speed of light in air is 3 x 108 m/s

View Answer

Ans. a) For the same angle of incidence: The refractive ray in medium I deviates less than in medium II. Hence medium I is more denser than medium II

b) Refractive index of diamond = 2.42

Speed of light in air = 3 x 108 m/s

Speed of light in diamond = ?

n = Speed of light in air/Speed of light in diamond = c/v

v = c/n = 3 x 108/2.42

v = 1.24 x 108 m/s


47. A student focused the image of a candle flame on a white screen by placing the flame at various distances from a convex lend. He noted his observations.

a) From the above table, find the focal length of lens without using lens formula.

b) Which set of observations is incorrect and why?

c) In which case the size of object and image will be same? Give reason for your answer.

View Answer

Ans. In observation (iii) of the table given u = 30 cm, v = 30 cm, which is only possible when u = v = 2f (at C)

2f = 30 or f = 15 cm


48. (a) Define power of a lens and write its SI unit.

(b) A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the lens, if image size is equal to the object size? Also find the power of the lens.

View Answer

Ans. Power of a lens is the ability of a lens to bend a ray of light incident upon it. It is equal to the reciprocal of the focal length of the lens.

P = 1/f

If f is measured in m then unit of power is dioptre (D)

(b) v = +50 cm

m = 1

P = ?

Since, m = 1, m = v/u = 1

Or u = v = 50 cm

i.e., v and u both are at centre of curvatures C = 2f = 50 or f = 25 cm.

P = 1/f

P = +100/25 D

P = + 4D


49. (a) A ray of light falls normally on a face of a glass slab. What are the values of angle of incidence and angle of refraction of this ray?

(b) Light enters from air to a medium X. Its speed in medium X becomes 1.5 x 108 m/s. Find the refractive index of medium X.

View Answer

Ans. a) When a ray of light falls normally on a glass slab then I = 0, and r = 0

b) vm = 1.5 x 108 m/s

c = 3 x 108 m/s

We know refractive index

n = c/vm

= 3 x 108/1.5 x 108

n = 2


50. (a) Water has refractive index 1.33 and alcohol has refractive index 1.36. Which of the two medium is optically denser? Give reason for your answer. Draw a ray diagram to show the path of a ray of light passing obliquely from water to alcohol.

(b) The absolute refractive index of diamond is 2.42 and the absolute refractive index of glass is 1.50. Find the refractive index of diamond with respect to glass.

View Answer

Ans. a) More refractive index means more optical denser medium. Here refractive index of water is 1.33 and of alcohol is 1.36.

Hence alcohol is more optical denser than water.

b)


51. A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15 cm. Give the location of image and magnification. Describe what happens to the image as the needle is moved farther from the mirror.

View Answer

Ans. Given u = -12 cm

f = +15 cm

h1 = 4.5 cm

v = ?, m = ?

Mirror formula

1/v + 1/u = 1/f

1/v = 1/f – 1/u = 1/5 – 1/-12 = 1/15 + 1/12

v = + 6.6 cm

m = -v/u = -6.6/-12 = 0.55

Size of image is smaller than size of object.


52. (a) State Snell’s law of refraction.

(b) When a ray of light travelling in air enters obliquely into a glass slab, it is observed that the light ray emerges parallel to the incident ray but it is shifted sideways slightly. Draw a ray diagram to illustrate it.

View Answer

(a) Snell’s law = sin i/sin r = constant (Refractive index of the medium)

(b)


53. A student wants to project the image of a candle flame on a screen 60 cm in front of a mirror by keeping the flame at a distance of 15 cm from its pole.

a) Write the type of mirror he should use.

b) Find the linear magnification of the image produced.

c) What is the distance between the object and its image.

d) Draw a ray diagram to show the image formation in this case.

View Answer

Ans. Given

v = -60 cm

u = -15 cm

a) Since the image is real the mirror is concave

b) m = -v/u = -(-60)/(-15) = -4

m = -4

c) Distance between object position and image position = 60 – 15 = 45 cm

d)


54. Discuss the position and nature of the image formed by a concave mirror when the object is moved from infinity towards the pole of the mirror.

View Answer

Ans. When an object is moved from infinity toward the pole of a concave mirror then its image moves from focus to infinity.


55. State the laws of refraction.

View Answer

Ans. Snell’s laws of refraction

a) Incident ray, refracted ray and normal to the point of incidence lie in the same plane.

b) sin i/ sin 4 = ½ n


56. (a) Define radius of curvature and focal length of a spherical mirror and show it on a figure.

(b) Write relation between radius of curvature and focal length of a spherical mirror.

View Answer

Ans.

(a) Distance between pole and centre of curvature is known as radius of curvature or the radius of the sphere of which mirror is a part is called radius of curvature.

(b) Focal length of a mirror is half of the radius of curvature

f = R/2


57. An object of height 5 cm is placed perpendicular to the principal axis of a concave lens of focal length 10 cm. If the distance of the object from the optical centre of the lens is 20 cm, determine the position, nature and size of the image formed using the lens formula.

View Answer

Ans.

Given object height h = + 5cm for a concave lens

u = -20 cm, f = -10 cm, v = ?

1/f = 1/v – 1/u

1/v = 1/f + 1/u

1/v = 1/-10 + 1/-20 = -3/20

V = -20/3 cm = -6.66 cm

Image formed is virtual, erect

M = h’/h = v/u

H’ = h x v/u = 5 x (-20/3 x 1/-20) cm

= 5 x 1/3 cm = 5/3 cm = 1.66 cm


58. If the image formed by a mirror for all positions of the object placed in front of it is always erect and diminished, what type of mirror is it? Draw a ray diagram to justify your answer. Where and why do we generally use this type of mirror?

View Answer

Ans. Only in convex mirror, for all positions of the object placed in front of it is always virtual, erected and diminished. Hence this mirror is convex mirror.

Convex mirrors are used in automobiles as a rear view mirror because of wider field of view and formation of erect image.


59. The nature, size and position of image of an object produced by a lens or mirror as shown below. Identify the lens/mirror (X) used in each case and draw the corresponding complete ray diagram, (size of the object about half of the image).

View Answer

Ans. a) Convex lens when object is in between F and C(2F)

b) Concave mirror when object is in between P and F its enlarged, erected and virtual image is formed.


60. (a) Calculate the distance at which an object should be placed in front of a convex lens of focal length 10 cm to obtain a virtual image of double its size.

(b) In the above given case, find the magnification, if image formed is real. Express it in terms of relation between v and u.

View Answer

Ans. Given f= +10 cm, u= ?

For virtual image

m = +2

As m = v/u or v/u = 2

v = 2u ———- (1)

1/v – 1/u = 1/f ———— (2)

Substituting (1) in (2)

1/2u – 1/u = 1/10

-1/2u = 1/10

u = -5 cm

For real image, f = 10 cm, m = -2

v/u = -2, v = -2u

1/v – 1/u = 1/f

1/-2u – 1/u = 1/10

-3/2u = 1/10

U = -15 cm


61. One half of a convex lens is covered with a black paper.

a) Show the formation of image of an object placed at 2F of such covered lens with the help of ray diagram. Mention the position and nature of image.

b) Draw the ray diagram for same object at same position in front of the same lens, but now uncovered. Will there be any difference in the image obtained in the two cases? Give reason for your answer.

View Answer

Ans. If the lower half of the lens is covered even then it will form a complete real, inverted image of same size at C2(2F2) with reduced intensity of image.

b) There will be no change in the nature and position of the object except in later case the image will be brighter.


62. What is meant by power of a lens? Write its SI unit. A student uses a lens of focal length 40 cm and another of -20 cm. Write the nature and power of each lens.

View Answer

Ans. Power of lens is the ability of a lens to converge or diverge light rays passing through it. It is the reciprocal of the focal length.

S.I unit: If focal length is measured in metre then unit of power of a lens is Dioptre (D)

P = 1/f (D)

Power of first lens: Focal length = +40 cm. Focal length is positive hence it is a convex lens.

P1 = +100/f (cm) = +100/40 cm = +2.5 D

Power of second lens

Focal length = -20 cm

Its focal length is negative hence it is a concave lens

f2 = -20/100 m = -1/5 m

P2 = 1/f2 = -5D


63. State the laws of refraction of light. Explain the term ‘absolute refractive index of a medium’ and write an expression to relate it with the speed of light in vacuum.

View Answer

Ans. Laws of refraction:

a) The incident ray, refracted ray and normal to the point of incidence, all lie in the same plane.

b) The ratio of sine of incident angle and sine of angle of refraction for a given pair of medium is constant.

Sin i/sin r = constant

Absolute refractive index of a medium is the ratio of speed of light in air or vacuum and speed of light in the medium.

Absolute refractive index

= (speed of light in air/vacuum)/(speed of light in medium)