Important Questions
1. State the law of constant proportion.
View AnswerAns. It states that, “In a pure chemical substance, the elements are always present in definite proportions by mass”.
Water (H2O) present in any form and from anywhere remains in fixed proportion i.e., 1:8
2. Give an example to show law of conservation of mass applies to physical changes also.
View AnswerAns. Law of conservation of mass states that mass can neither be created nor destroyed in a chemical reaction. However, this law applies to physical changes also.
For example, when ice melts into water, the mass of ice equals to the mass of water, i.e., the mass is conserved. This verifies the law of conservation of mass.
3. Define ‘atomic mass unit’. How is it linked with relative atomic mass?
View AnswerAtomic mass unit (u) is 1/12 of the mass of one atom of C-12.
Relative atomic mass of the atom of an element is the average mass of the atom as compared to 1/12th of the mass of C-12 atom.
4. How do you know the presence of atoms if they do not exist independently for most of the elements?
View AnswerAtoms of most of the elements do not exist independently. However, they combine in specific numbers to form molecules or ions which we can feel and know about their presence.
For eg.
A molecule of H2SO4 consists of 2 atoms of H + 1 atom of S + 4 atoms of O
A molecule of C12H22O11 consists of 12 atoms of C + 22 atoms of H + 11 atoms of O
Ammonium ion (NH4+) consists of 1 atom of N + 4 atoms of H
5. Mention two postulates of Dalton’s atomic theory that explain:
(a) Law of conservation of mass
View AnswerAns. The elements consists of atoms and that atoms can neither be created nor destroyed” can be used to explain the law of conservation of mass.
Mass (reactants) = mass (products)
(b) Law of constant proportions
View AnswerA pure chemical compound always consists of the same elements that are combined together in a fixed (or definite) proportion by mass.
6. Find the ratio of mass of the combining elements in the following compounds:
(a) CaCO3
View AnswerAns. 40 : 12 : 48 => 10 : 3 : 12
(b) MgCl2
View AnswerAns. 24 : 71
(c) H2SO4
View AnswerAns. 2 : 32 : 64 =>1 : 16 : 32
7. If the law of constant proportion is true, what weights of these elements will be present in 1.5g of another sample of Calcium Carbonate?
View AnswerCaCO3
Molecular mass = 40 + 12 + 48 = 100g
100 g of CaCO3 –> 40 g of Ca
1.5 g à 40/100 x 1.5 = 0.6 g
100 g of CaCO3 –> 12 g of C
1.5 g à 12/100 x 1.5 = 0.18 g
100 g of CaCO3 –> 48 g of O
1.5 g à 48/100 x 1.5 = 0.72 g
8. Write the chemical symbols of two elements:
(i) Which are formed from the first letter of the elements’ name?
View AnswerC, O, H, etc
(ii) Whose names have been taken from the names of the elements in Latin?
View AnswerFe, Au, Ag, etc
(iii) Which of are formed from the first two letters of the elements’ name?
View AnswerAr, Ne, He, etc
9. An element has valency 3. Write the formula of its oxide.
View AnswerE O
3 2
= E2O3
10. What are polyatomic ions? Give two examples.
View AnswerAns. A group of atoms having a charge is known as polyatomic ion.
Eg. NH4+, SO42-
11. Give one example each of
(i) Monovalent cation – Na+, Li+, K+, NH4+
(ii) Bivalent cation – Mg2+, Ca2+
(iii) Monovalent anion – OH–, H–, Cl–
(iv) Bivalent anion – O2-, S2-
12. What is meant by a chemical formula? Give Examples.
View AnswerAns. A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.
Eg. Chemical formula of ammonia is NH3, Water is H2O, Carbon dioxide is CO2
13. Write down the formula of:
(i) Sodium oxide
View AnswerNa O
1+ 2-
=Na2O
(ii) Aluminium oxide
View AnswerAl O
3+ 2-
Al2O3
(iii) Sodium sulphide
View AnswerNa S
1+ 2-
Na2S
(iv) Magnesium hydroxide
View AnswerMg (OH)
2+ 1-
Mg(OH)2
14. State two examples in each case and write their chemical formulae:
(a) Molecules having one kind of atoms only
View AnswerAns. H2, O2, N2
(b) Molecules having two different kinds of atoms
View AnswerAns. H2O, CO2, HCl
(c) Molecules having three different kinds of atoms.
View AnswerAns. CaCO3, H2SO4, NaOH
15. Write the formula and the names of the ions formed by the combination of
(i) Fe3+ and SO42-
View AnswerFe SO4
3+ 2-
Fe2(SO4)3 – Iron (III) sulphate
(ii) NH4+ and CO32-
View AnswerNH4 CO3
1+ 2-
(NH4)2CO3 – Ammonium Carbonate
16. What is an ion? Give one difference between cation and anion.
View AnswerAns. Charged atom is called as an ion. The ion can be positively charge called cation or negatively charged called anion.
Eg. Cation – Na+
Anion – Cl–
17. Define atomicity. Write the atomicity of the following molecules:
(i) Sulphur
(ii) Phosphorus
View AnswerAns. It is the number of atoms present in one molecule of a substance
(i) 8
(ii) 4
18. What are ionic and molecular compounds? Give examples.
View AnswerAns
Ionic compound | Molecular compound |
Made up of combination of opposite ions | Made up of atoms by sharing of electrons |
Eg. Na+ Cl– | Eg. H2O |
Due to transfer of electrons | Exists as neutral substance |
19. Write down the names of compounds represented by the following formulae:
View Answer(i) Al2(SO4)3 – Aluminium Sulphate
(ii) CaCl2 – Calcium Chloride
(iii) K2SO4 – Potassium Sulphate
(iv) KNO3 – Potassium Nitrate
(v) CaCO3 – Calcium Carbonate
20. How many atoms are present in
(i) H2S molecule – 3 atoms
(ii) PO43- – 5 atoms
[/expand]21. Give the names of the elements present in the following compounds
View Answer(a) Quick lime – CaO – Calcium and Oxygen
(b) Hydrogen Bromide – HBr – Hydrogen and Bromine
(c) Baking Soda – NaHCO3 – Sodium, Carbon, Hydrogen and Oxygen
(d) Potassium sulphate – K2SO4 – Sulphar, Oxygen, Potassium
22. What is molar mass? What are its units?
View AnswerAns. Mass of 1 mole of a substance. Unit – g/mol
23. Distinguish between molecular mass and molar mass.
View AnswerAns.
Molecular Mass | Molar Mass |
The molecular mass of a substance is the sum of the atomic masses of all atoms in a molecule | The mass of 1 mole of any substance is called is its molar mass. |
H2O = 1×2 + 16 = 18u | Eg. 18g/mol |
24. Define one mole, illustrate its relationship with Avogadro constant.
View AnswerAns. One mole of any species (atoms, molecules, ions or particles) is that quantity in number having mass equal to its atomic or molecular mass in grams.
The number of particles (atoms, molecules or ions) present in 1 mole of any substance is fixed, with a value of 6.022 x 1023. This number is called Avogadro constant or Avogadro number.
25. What is the mass of:
(a) 0.2 mole of oxygen atoms
(b) 0.5 mole of water molecules
View Answer(a) Number of moles (n) = G.M/M.M
M.M of oxygen = 16g
n = 0.2
G.M = n x M.M
= 0.2 x 16
= 3.2 g
(b) M.M of H2O = 2 x 1 + 1 x 16 = 18g
n = 0.5
G.M = n x M.M
= 0.5 x 18
= 9 g
26. Calculate the number of molecules of SO2 present in 44 g of it.
View AnswerM.M of SO2 = 32 + 2 x 16 = 64g
Number of molecules = G.M/M.M x Avogadro constant
= 44/64 x 6.023 x 1023
= (3.011 x 11 x 1023)/8
= 3.76 x 1023
27. If one mole of carbon atoms weights 12 grams, what is the mass (in grams) of 1 atom of carbon?
View Answer6.022 x 1023 C-atoms –>12 g of C
1 atom –> 12/6.022 x 1023
1 atom of C –>1.9 x 10-23 g
28. Calculate the molar mass of the following substances
(a) Ethyne, C2H2
(b) Sulphur molecule, S8
(c) Phosphorus molecule, P4 (Atomic mass of phosphorus = 31)
(d) Hydrochloric acid, HCl
(e) Nitric acid, HNO3
View AnswerAns. (a) 2 x 12 + 2 x 1 = 24 + 2 = 26 g/mol
(b) 8 x 32 = 256 g/mol
(c) 4 x 31 = 124 g/mol
(d) 1 x 1 + 35.5 = 36.5 g/mol
(e) 1 x 1 + 1 x 14 + 2 x 16 = 1 + 14 + 32 = 47 g/mol
29. What is the mass of:
(a) 1 mole of nitrogen atoms
View AnswerM.M of nitrogen = 14g
n = 1 mole
G.M = n x M.M
=1 x 14
= 14 g/mol
(b) 4 moles of aluminium atoms (Atomic mass of aluminium = 27)
View AnswerM.M of Al = 27
n = 4 moles
G.M = n x M.M
= 4 x 27
= 108g/mol
(c) 10 moles of sodium sulphite (Na2SO3)
View AnswerM.M of sodium sulphite = 2 x 23 + 32 + 3 x 16 = 126 g/mol
n = 10 mole
G.M = n x M.M
= 10 x 126
= 1260 g/mol
29. How many gram molecules of H2SO4 are present in 4.9 g of the acid?
View Answer1 mole –>1 g atoms
- 1 g molecules
- 1 g ions
M.M = 2 x 1 + 32 + 4 x 16 = 98 g/mol
G.M = 4.9 g
n = G.M/M.M
= 4.9/98 = 0.05 g molecules
30. Convert into mole
(a) 12 g of oxygen gas (O2)
(b) 20 gm of water (H2O)
(c) 22 g of Carbon dioxide (CO2)
View Answer(a) M.M of oxygen gas = 2 x 16 = 32g
G.M = 12 g
n = G.M/M.M = 12/32 moles = 0.375 moles
(b) M.M of water = 2 x 1 + 16 = 18g
G.M = 20g
n = G.M/M.M = 20/18 moles = 1.11 moles
(c) M.M of Carbon dioxide = 12 + 2 x 16 = 44g
G.M = 22 g
n = 22/44 moles = 0.5 moles